What are the solutions to the equation x(4x-5)=0 ?

The solutions to the equation x(4x-5)=0 are x=0,x= 5/4

Find the zeros of x(4x-5)=0

The zeros of x(4x-5)=0 are x=0,x= 5/4

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x (4 x - 5) = 0

x = 0, x = \frac{5}{4}

Decimal Notation

x = 0, x = 1.25

Solution steps

x (4 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 4 x - 5 = 0

Solve

4 x - 5 = 0 : x = \frac{5}{4}

The solutions to the quadratic equation are:

x = 0, x = \frac{5}{4}

- 91.5 x^{2} - 18 x + 73.5 = 0

x^{2} - 16 x + 48 = 9

y, 9 x^{2} - 4 y^{2} - 36 x - 16 y + 20 = 0

(x + 6)^{2} - 32 = 0

k^{2} + 5 k = - 6

What are the solutions to the equation x(4x-5)=0 ?
The solutions to the equation x(4x-5)=0 are x=0,x= 5/4
Find the zeros of x(4x-5)=0
The zeros of x(4x-5)=0 are x=0,x= 5/4