What are the solutions to the equation -x^2-3x+2=x+6 ?

The solutions to the equation -x^2-3x+2=x+6 are x=-2

Find the zeros of -x^2-3x+2=x+6

The zeros of -x^2-3x+2=x+6 are x=-2

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- x^{2} - 3 x + 2 = x + 6

x = - 2

Solution steps

- x^{2} - 3 x + 2 = x + 6

Move

6

to the left side

- x^{2} - 3 x - 4 = x

Move

x

to the left side

- x^{2} - 4 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

(- 4)^{2} - 4 (- 1) (- 4) = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 ( - 1 )}

x = \frac{- ( - 4 )}{2 ( - 1 )}

\frac{- ( - 4 )}{2 ( - 1 )} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

y^{2} + 4 k y + 5

x^{2} - 14 x = 49

3 x^{2} + 24 x + 40 = 0

- 2 - 3 (x - 5)^{2} = - 29

(2 x - 1)^{2} - 16 = 9

What are the solutions to the equation -x^2-3x+2=x+6 ?
The solutions to the equation -x^2-3x+2=x+6 are x=-2
Find the zeros of -x^2-3x+2=x+6
The zeros of -x^2-3x+2=x+6 are x=-2