What are the solutions to the equation roots x^2+12x+37 ?

The solutions to the equation roots x^2+12x+37 are x=-6+i,x=-6-i

Find the zeros of roots x^2+12x+37

The zeros of roots x^2+12x+37 are x=-6+i,x=-6-i

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roots

x^{2} + 12 x + 37

x = - 6 + i, x = - 6 - i

Solution steps

x^{2} + 12 x + 37

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 12 x + 37 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 37}{2 \cdot 1}

Simplify

1 2^{2} - 4 \cdot 1 \cdot 37 : 2 i

x_{1, 2} = \frac{- 12 \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 i}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 i}{2 \cdot 1}

x = \frac{- 12 + 2 i}{2 \cdot 1} : - 6 + i

x = \frac{- 12 - 2 i}{2 \cdot 1} : - 6 - i

The solutions to the quadratic equation are:

x = - 6 + i, x = - 6 - i

3 u^{2} = 27 u

5 (x - 7)^{2} + 72 = 112

x^{2} + 4 x + 20 = 0

- 20 x^{2} = 4 x

- 3 x^{2} - 7 x + 5

What are the solutions to the equation roots x^2+12x+37 ?
The solutions to the equation roots x^2+12x+37 are x=-6+i,x=-6-i
Find the zeros of roots x^2+12x+37
The zeros of roots x^2+12x+37 are x=-6+i,x=-6-i