What are the solutions to the equation 5(x-7)^2+72=112 ?

The solutions to the equation 5(x-7)^2+72=112 are x=2sqrt(2)+7,x=-2sqrt(2)+7

Find the zeros of 5(x-7)^2+72=112

The zeros of 5(x-7)^2+72=112 are x=2sqrt(2)+7,x=-2sqrt(2)+7

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5 (x - 7)^{2} + 72 = 112

x = 22 + 7, x = - 22 + 7

Decimal Notation

x = 9.82842 \dots, x = 4.17157 \dots

Solution steps

5 (x - 7)^{2} + 72 = 112

Move

72

to the right side

5 (x - 7)^{2} = 40

Divide both sides by

5

(x - 7)^{2} = 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 7 = 8 : x = 22 + 7

Solve

x - 7 = - 8 : x = - 22 + 7

The solutions to the quadratic equation are:

x = 22 + 7, x = - 22 + 7

x^{2} + 4 x + 20 = 0

- 20 x^{2} = 4 x

- 3 x^{2} - 7 x + 5

60 x^{2} - 180 x = 0

f, f^{- 1} (x) = x^{2} - 2

What are the solutions to the equation 5(x-7)^2+72=112 ?
The solutions to the equation 5(x-7)^2+72=112 are x=2sqrt(2)+7,x=-2sqrt(2)+7
Find the zeros of 5(x-7)^2+72=112
The zeros of 5(x-7)^2+72=112 are x=2sqrt(2)+7,x=-2sqrt(2)+7