What are the solutions to the equation s^2-2s-14=0 ?

The solutions to the equation s^2-2s-14=0 are s=1+sqrt(15),s=1-sqrt(15)

Find the zeros of s^2-2s-14=0

The zeros of s^2-2s-14=0 are s=1+sqrt(15),s=1-sqrt(15)

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s^{2} - 2 s - 14 = 0

s = 1 + 15, s = 1 - 15

Decimal Notation

s = 4.87298 \dots, s = - 2.87298 \dots

Solution steps

s^{2} - 2 s - 14 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 14) = 215

s_{1, 2} = \frac{- ( - 2 ) \pm 2 15}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 2 ) + 2 15}{2 \cdot 1}, s_{2} = \frac{- ( - 2 ) - 2 15}{2 \cdot 1}

s = \frac{- ( - 2 ) + 2 15}{2 \cdot 1} : 1 + 15

s = \frac{- ( - 2 ) - 2 15}{2 \cdot 1} : 1 - 15

The solutions to the quadratic equation are:

s = 1 + 15, s = 1 - 15

3 x^{2} + 12 x + 20 = 0

- 5 x^{2} + 35 x - 50 = - 200

4 x^{2} = (x + 1)^{2} + b

y, (x - 1)^{2} + y^{2} = 0

x^{2} + 16 x + 71

What are the solutions to the equation s^2-2s-14=0 ?
The solutions to the equation s^2-2s-14=0 are s=1+sqrt(15),s=1-sqrt(15)
Find the zeros of s^2-2s-14=0
The zeros of s^2-2s-14=0 are s=1+sqrt(15),s=1-sqrt(15)