What is the answer to 3^{5x}9^{x^2}=27 ?

The answer to 3^{5x}9^{x^2}=27 is x= 1/2 ,x=-3

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3^{5x}9^{x^2}=27

3^{5 x} 9^{x^{2}} = 27

x = \frac{1}{2}, x = - 3

Decimal Notation

x = 0.5, x = - 3

Solution steps

3^{5 x} \cdot 9^{x^{2}} = 27

Apply exponent rules

5 x + 2 x^{2} = 3

Solve

5 x + 2 x^{2} = 3 : x = \frac{1}{2}, x = - 3

x = \frac{1}{2}, x = - 3

3^{2 x} = 1

3^{x + \frac{1}{2}} \times 3^{x - 2} = 1

3^{4 x} = 7^{2 - 5 x}

2^{3 k - 1} \cdot 2^{5 k - 7} = 16

4^{2 x} = 62 5^{3 x + 5}

What is the answer to 3^{5x}9^{x^2}=27 ?
The answer to 3^{5x}9^{x^2}=27 is x= 1/2 ,x=-3
Solve for x: 3^{5x}9^{x^2}=27
The solution is x= 1/2 ,x=-3