What are the solutions to the equation x^4-30x^2+289=0 ?

The solutions to the equation x^4-30x^2+289=0 are x=4+i,x=-4-i,x=4-i,x=-4+i

Find the zeros of x^4-30x^2+289=0

The zeros of x^4-30x^2+289=0 are x=4+i,x=-4-i,x=4-i,x=-4+i

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x^{4} - 30 x^{2} + 289 = 0

x = 4 + i, x = - 4 - i, x = 4 - i, x = - 4 + i

Solution steps

x^{4} - 30 x^{2} + 289 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} - 30 u + 289 = 0

Solve

u^{2} - 30 u + 289 = 0 : u = 15 + 8 i, u = 15 - 8 i

u = 15 + 8 i, u = 15 - 8 i

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 15 + 8 i : x = 4 + i, x = - 4 - i

Solve

x^{2} = 15 - 8 i : x = 4 - i, x = - 4 + i

The solutions are

x = 4 + i, x = - 4 - i, x = 4 - i, x = - 4 + i

0.04 x^{4} - 3.24 = 0

3 \times 1 0^{8} = x^{6} \times 1 0^{14}

x^{3} + x^{2} - 12 x - 12 = 0

6 x^{3} + 25 x^{2} + 2 x - 8

3 x^{3} - 22 x^{2} + 5 x + 14 = 0

What are the solutions to the equation x^4-30x^2+289=0 ?
The solutions to the equation x^4-30x^2+289=0 are x=4+i,x=-4-i,x=4-i,x=-4+i
Find the zeros of x^4-30x^2+289=0
The zeros of x^4-30x^2+289=0 are x=4+i,x=-4-i,x=4-i,x=-4+i