What are the solutions to the equation (-11x^2+62)(-9x^2+25)-(-11)(-11)=0 ?

The solutions to the equation (-11x^2+62)(-9x^2+25)-(-11)(-11)=0 are

Find the zeros of (-11x^2+62)(-9x^2+25)-(-11)(-11)=0

The zeros of (-11x^2+62)(-9x^2+25)-(-11)(-11)=0 are

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(- 11 x^{2} + 62) (- 9 x^{2} + 25) - (- 11) (- 11) = 0

x = \frac{833 + 128005}{3 22}, x = - \frac{833 + 128005}{3 22}, x = \frac{833 - 128005}{3 22}, x = - \frac{833 - 128005}{3 22}

Decimal Notation

x = 2.45235 \dots, x = - 2.45235 \dots, x = 1.54922 \dots, x = - 1.54922 \dots

Solution steps

(- 11 x^{2} + 62) (- 9 x^{2} + 25) - (- 11) (- 11) = 0

Expand

(- 11 x^{2} + 62) (- 9 x^{2} + 25) - (- 11) (- 11) : 99 x^{4} - 833 x^{2} + 1429

99 x^{4} - 833 x^{2} + 1429 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

99 u^{2} - 833 u + 1429 = 0

Solve

99 u^{2} - 833 u + 1429 = 0 : u = \frac{833 + 128005}{198}, u = \frac{833 - 128005}{198}

u = \frac{833 + 128005}{198}, u = \frac{833 - 128005}{198}

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = \frac{833 + 128005}{198} : x = \frac{833 + 128005}{3 22}, x = - \frac{833 + 128005}{3 22}

Solve

x^{2} = \frac{833 - 128005}{198} : x = \frac{833 - 128005}{3 22}, x = - \frac{833 - 128005}{3 22}

The solutions are

x = \frac{833 + 128005}{3 22}, x = - \frac{833 + 128005}{3 22}, x = \frac{833 - 128005}{3 22}, x = - \frac{833 - 128005}{3 22}

1 - \frac{5}{2} x + 2 x^{2} - \frac{1}{2} x^{3} = 0

10 x^{3} - 39 x^{2} + 29 x - 6 = 0

4 x^{3} - 54 x^{2} + 240 x - 350 = 0

x^{3} - 64 = 0

y, 3 x^{3} + 9 x y^{2} = 5 x^{3}

What are the solutions to the equation (-11x^2+62)(-9x^2+25)-(-11)(-11)=0 ?
The solutions to the equation (-11x^2+62)(-9x^2+25)-(-11)(-11)=0 are
Find the zeros of (-11x^2+62)(-9x^2+25)-(-11)(-11)=0
The zeros of (-11x^2+62)(-9x^2+25)-(-11)(-11)=0 are