What are the solutions to the equation -x^3+x^2+10x+8=0 ?

The solutions to the equation -x^3+x^2+10x+8=0 are x=-1,x=-2,x=4

Find the zeros of -x^3+x^2+10x+8=0

The zeros of -x^3+x^2+10x+8=0 are x=-1,x=-2,x=4

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- x^{3} + x^{2} + 10 x + 8 = 0

x = - 1, x = - 2, x = 4

Solution steps

- x^{3} + x^{2} + 10 x + 8 = 0

Factor

- x^{3} + x^{2} + 10 x + 8 : - (x + 1) (x + 2) (x - 4)

- (x + 1) (x + 2) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x + 2 = 0 or x - 4 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x + 2 = 0 : x = - 2

Solve

x - 4 = 0 : x = 4

The solutions are

x = - 1, x = - 2, x = 4

x^{3} - 3 x^{2} + 3 x + 7 = 0

- x^{3} + 6 x^{2} - 11 x + 6

3 x^{3} - 17 x^{2} + 18 x + 8 = 0

f, f x = 4 x^{3} - 6 x^{2}

x (2 x^{2} - 41) = 225

What are the solutions to the equation -x^3+x^2+10x+8=0 ?
The solutions to the equation -x^3+x^2+10x+8=0 are x=-1,x=-2,x=4
Find the zeros of -x^3+x^2+10x+8=0
The zeros of -x^3+x^2+10x+8=0 are x=-1,x=-2,x=4