What is the answer to 1+log_{x}(125)=6 ?

The answer to 1+log_{x}(125)=6 is x=\sqrt[5]{125}

Solve for x: 1+log_{x}(125)=6

The solution is x=\sqrt[5]{125}

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1 + lo g_{x} (125) = 6

x = 5125

Decimal

x = 2.62652 \dots

Solution steps

1 + lo g_{x} (125) = 6

Move

1

to the right side

lo g_{x} (125) = 5

Apply log rules

\frac{1}{lo g _{125} ( x )} = 5

Multiply both sides by

lo g_{125} (x)

\frac{1}{lo g _{125} ( x )} lo g_{125} (x) = 5 lo g_{125} (x)

Simplify

1 = 5 lo g_{125} (x)

Switch sides

5 lo g_{125} (x) = 1

Divide both sides by

5

lo g_{125} (x) = \frac{1}{5}

Apply log rules

x = 5125

Verify Solutions:

x = 5125

True

The solution is

x = 5125

lo g_{x} (27) = x

ln (x + 12) - ln (x) = 5

lo g_{2} (- x) = - 5

\frac{( 1 - ln ( x ) )}{x ^{2}} = 0

ln (x^{2}) = - 1

What is the answer to 1+log_{x}(125)=6 ?
The answer to 1+log_{x}(125)=6 is x=\sqrt[5]{125}
Solve for x: 1+log_{x}(125)=6
The solution is x=\sqrt[5]{125}