What is the answer to ln(2x-1)=-3 ?

The answer to ln(2x-1)=-3 is x=(1+e^3)/(2e^3)

Solve for x: ln(2x-1)=-3

The solution is x=(1+e^3)/(2e^3)

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ln (2 x - 1) = - 3

x = \frac{1 + e ^{3}}{2 e ^{3}}

Decimal

x = 0.52489 \dots

Solution steps

ln (2 x - 1) = - 3

Apply log rules

2 x - 1 = \frac{1}{e ^{3}}

Solve

2 x - 1 = \frac{1}{e ^{3}} : x = \frac{1 + e ^{3}}{2 e ^{3}}

x = \frac{1 + e ^{3}}{2 e ^{3}}

lo g_{3} (x^{2} - 5 x - 3) = 2

lo g_{10} (x - 1) = 0

lo g_{3} (x^{2} - 5 x + 9) = 2

y, lo g_{y} (\frac{1}{x}) = - 2

lo g_{2} (x^{2} + 4 x + 3) = 3

What is the answer to ln(2x-1)=-3 ?
The answer to ln(2x-1)=-3 is x=(1+e^3)/(2e^3)
Solve for x: ln(2x-1)=-3
The solution is x=(1+e^3)/(2e^3)