What is factor x^3+4x^2-3x-18 ?

The solution to factor x^3+4x^2-3x-18 is (x-2)(x+3)^2

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factor x^3+4x^2-3x-18

factor

x^{3} + 4 x^{2} - 3 x - 18

(x - 2) (x + 3)^{2}

Solution steps

x^{3} + 4 x^{2} - 3 x - 18

Use the rational root theorem

= (x - 2) \frac{x ^{3} + 4 x ^{2} - 3 x - 18}{x - 2}

\frac{x ^{3} + 4 x ^{2} - 3 x - 18}{x - 2} = x^{2} + 6 x + 9

= (x - 2) (x^{2} + 6 x + 9)

Factor

x^{2} + 6 x + 9 : (x + 3) (x + 3)

= (x - 2) (x + 3) (x + 3)

Apply exponent rule:

aa = a^{2}

(x + 3) (x + 3) = (x + 3)^{2}

= (x - 2) (x + 3)^{2}

- 4 x^{2} - 7 x - 2 = 0

- 2 + 23 i

4 x^{2} + 8 x + 7 = 0

3 (- \frac{1}{3})^{3} + (- \frac{1}{3})^{2} - 6 (- \frac{1}{3}) - 2

(\frac{10 x ^{3} y ^{2}}{5 x ^{- 3} y ^{4}})^{- 3}

What is factor x^3+4x^2-3x-18 ?
The solution to factor x^3+4x^2-3x-18 is (x-2)(x+3)^2