What are the solutions to the equation x^2-2x-27=-5x+1 ?

The solutions to the equation x^2-2x-27=-5x+1 are x=4,x=-7

Find the zeros of x^2-2x-27=-5x+1

The zeros of x^2-2x-27=-5x+1 are x=4,x=-7

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x^{2} - 2 x - 27 = - 5 x + 1

x = 4, x = - 7

Solution steps

x^{2} - 2 x - 27 = - 5 x + 1

Move

1

to the left side

x^{2} - 2 x - 28 = - 5 x

Move

5 x

to the left side

x^{2} + 3 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 28) = 11

x_{1, 2} = \frac{- 3 \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 11}{2 \cdot 1}, x_{2} = \frac{- 3 - 11}{2 \cdot 1}

x = \frac{- 3 + 11}{2 \cdot 1} : 4

x = \frac{- 3 - 11}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 4, x = - 7

5 x + a y + 5 y + a x

4 x^{2} - 32 x + 64 = 0

\frac{3 n ^{2} - 5 n - 2}{2 n - 4}

x^{2} - 10 x + 23 = 0

16 - 83 + 3

What are the solutions to the equation x^2-2x-27=-5x+1 ?
The solutions to the equation x^2-2x-27=-5x+1 are x=4,x=-7
Find the zeros of x^2-2x-27=-5x+1
The zeros of x^2-2x-27=-5x+1 are x=4,x=-7