What is (-4a^{-2}b^4)/(8a^{-6)b^{-3}} ?

The solution to (-4a^{-2}b^4)/(8a^{-6)b^{-3}} is -(a^4b^7)/2

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simplify (-4a^{-2}b^4)/(8a^{-6)b^{-3}}

simplify

\frac{- 4 a ^{- 2} b ^{4}}{8 a ^{- 6} b ^{- 3}}

- \frac{a ^{4} b ^{7}}{2}

Solution steps

\frac{- 4 a ^{- 2} b ^{4}}{8 a ^{- 6} b ^{- 3}}

Factor the number:

8 = 4 \cdot 2

= \frac{- 4 a ^{- 2} b ^{4}}{4 \cdot 2 a ^{- 6} b ^{- 3}}

Cancel the common factor:

4

= \frac{- a ^{- 2} b ^{4}}{2 a ^{- 6} b ^{- 3}}

Simplify

\frac{a ^{- 2}}{a ^{- 6}} : a^{4}

= \frac{- a ^{4} b ^{4}}{2 b ^{- 3}}

Simplify

\frac{b ^{4}}{b ^{- 3}} : b^{7}

= \frac{- a ^{4} b ^{7}}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{a ^{4} b ^{7}}{2}

3 (4 x - 1) (4 x + 3) = 48 x

- 2 r^{2} - 12 r + 10 = - 12

x^{2} + 4 x - 5 = 0

4 r^{2} + 44 r + 121 = 0

9 (x + 2)^{2} - 4 = 2

What is (-4a^{-2}b^4)/(8a^{-6)b^{-3}} ?
The solution to (-4a^{-2}b^4)/(8a^{-6)b^{-3}} is -(a^4b^7)/2