What are the solutions to the equation (x^2-4)=0 ?

The solutions to the equation (x^2-4)=0 are x=2,x=-2

Find the zeros of (x^2-4)=0

The zeros of (x^2-4)=0 are x=2,x=-2

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(x^{2} - 4) = 0

x = 2, x = - 2

Solution steps

(x^{2} - 4) = 0

x^{2} - 4 = 0

Move

4

to the right side

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

(8)^{2}

\frac{x - 4}{x ^{2} - 49} < 0

(x + 5) (x - 5) = - 9

6 b^{2} - 12 b - 90 = 0

- 3 x^{2} - 15 + 5 x = 4

What are the solutions to the equation (x^2-4)=0 ?
The solutions to the equation (x^2-4)=0 are x=2,x=-2
Find the zeros of (x^2-4)=0
The zeros of (x^2-4)=0 are x=2,x=-2