What is factor 6y^2+41y+13 ?

The solution to factor 6y^2+41y+13 is (3y+1)(2y+13)

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factor 6y^2+41y+13

factor

6 y^{2} + 41 y + 13

(3 y + 1) (2 y + 13)

Solution steps

6 y^{2} + 41 y + 13

Break the expression into groups

= (6 y^{2} + 2 y) + (39 y + 13)

Factor out

2 y

from

6 y^{2} + 2 y : 2 y (3 y + 1)

Factor out

13

from

39 y + 13 : 13 (3 y + 1)

= 2 y (3 y + 1) + 13 (3 y + 1)

Factor out common term

3 y + 1

= (3 y + 1) (2 y + 13)

7 x^{2} - 13 x - 1 = 0

4 x^{2} + 8 x + 20 = 0

2 x^{4} - 7 x^{3} + 3 x^{2} + 8 x - 4

3 X^{2} = - 99

(9 x)^{2}

What is factor 6y^2+41y+13 ?
The solution to factor 6y^2+41y+13 is (3y+1)(2y+13)