What is factor x^3+4x^2+3x+12 ?

The solution to factor x^3+4x^2+3x+12 is (x+4)(x^2+3)

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factor x^3+4x^2+3x+12

factor

x^{3} + 4 x^{2} + 3 x + 12

(x + 4) (x^{2} + 3)

Solution steps

x^{3} + 4 x^{2} + 3 x + 12

= (x^{3} + 4 x^{2}) + (3 x + 12)

Factor out

x^{2}

from

x^{3} + 4 x^{2} : x^{2} (x + 4)

Factor out

3

from

3 x + 12 : 3 (x + 4)

= x^{2} (x + 4) + 3 (x + 4)

Factor out common term

x + 4

= (x + 4) (x^{2} + 3)

(x - 2) (x + 1) (2 x + 3) \leq 0

\frac{5}{3 + 4 3}

∣ x + 1 ∣ + ∣ x - 1 ∣ = 2

(2 x + 7) (2 x - 7) = 0

\frac{( 1 + i ) ( 1 - i ) ^{4}}{( 1 + 2 i ) ^{3}}

What is factor x^3+4x^2+3x+12 ?
The solution to factor x^3+4x^2+3x+12 is (x+4)(x^2+3)