What is the tangent of f(x)=7sqrt(x),\at x=16 ?

The tangent of f(x)=7sqrt(x),\at x=16 is y= 7/8 x+14

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tangent of f(x)=7sqrt(x),\at x=16

tangent of

f (x) = 7 x, at x = 16

y = \frac{7}{8} x + 14

Solution steps

Find the tangent point:

(16, 28)

Find the slope of

f (x) = 7 x : \frac{df ( x )}{d x} = \frac{7}{2 x}

Compute the slope of

f (x) = 7 x

x = 16 : m = \frac{7}{8}

Find the line with slope m=

\frac{7}{8}

and passing through

(16, 28) : y = \frac{7}{8} x + 14

y = \frac{7}{8} x + 14

\int \frac{7}{x ^{8}} d x

\frac{1}{4 - x}

x \to 0 + lim (tan^{x} (x))

\frac{d y}{d x} - \frac{2 y}{x} = - x^{2} y^{2}

What is the tangent of f(x)=7sqrt(x),\at x=16 ?
The tangent of f(x)=7sqrt(x),\at x=16 is y= 7/8 x+14