What is the first derivative of 2x^2-2 ?

The first derivative of 2x^2-2 is 4x

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derivative of 2x^2-2

\frac{d}{d x} (2 x^{2} - 2)

4 x

Solution steps

\frac{d}{d x} (2 x^{2} - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (2)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (2) = 0

= 4 x - 0

Simplify

= 4 x

f (x) = 4 x^{2}, at x = 9

4 x^{- 1}

- 4 x^{2} + 6.25 x + 8, 2.5 x + 7

\int (sec (x) - 2 x tan (x) - 2 x) d x

\frac{d}{d x} (- 2 ln (\frac{3}{2} x))