What is laplacetransform sqrt(2)sin(sqrt(2)t) ?

The answer to laplacetransform sqrt(2)sin(sqrt(2)t) is 2/(s^2+2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform sqrt(2)sin(sqrt(2)t)

laplace transform

2 sin (2 t)

\frac{2}{s ^{2} + 2}

Solution steps

L {2 sin (2 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 2 L {sin (2 t)}

L {sin (2 t)} : \frac{2}{s ^{2} + 2}

= 2 \frac{2}{s ^{2} + 2}

Refine

2 \frac{2}{s ^{2} + 2} : \frac{2}{s ^{2} + 2}

= \frac{2}{s ^{2} + 2}

\frac{d y}{d x} y = \frac{x ^{3}}{3} - x

\frac{\partial}{\partial x} (cos^{6} (x^{8} y^{9}))

y^{^{''}} + 5 y^{^{'}} + 4 y = 0

\int \frac{10}{x ^{2}} d x

\frac{\partial}{\partial x} (7 e^{x} cos (yz))

What is laplacetransform sqrt(2)sin(sqrt(2)t) ?
The answer to laplacetransform sqrt(2)sin(sqrt(2)t) is 2/(s^2+2)