What is (d^3)/(dx^3)(1/(1+x^2)) ?

The answer to (d^3)/(dx^3)(1/(1+x^2)) is (24x(-x^2+1))/((x^2+1)^4)

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(d^3)/(dx^3)(1/(1+x^2))

\frac{d ^{3}}{d x ^{3}} (\frac{1}{1 + x ^{2}})

\frac{24 x ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{4}}

Solution steps

\frac{d ^{3}}{d x ^{3}} (\frac{1}{1 + x ^{2}})

\frac{d}{d x} (\frac{1}{1 + x ^{2}}) = - \frac{2 x}{( 1 + x ^{2} ) ^{2}}

= \frac{d ^{2}}{d x ^{2}} (- \frac{2 x}{( 1 + x ^{2} ) ^{2}})

\frac{d}{d x} (- \frac{2 x}{( 1 + x ^{2} ) ^{2}}) = - \frac{2 ( - 3 x ^{2} + 1 )}{( 1 + x ^{2} ) ^{3}}

= \frac{d}{d x} (- \frac{2 ( - 3 x ^{2} + 1 )}{( 1 + x ^{2} ) ^{3}})

\frac{d}{d x} (- \frac{2 ( - 3 x ^{2} + 1 )}{( 1 + x ^{2} ) ^{3}}) = \frac{24 x ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{4}}

= \frac{24 x ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{4}}

\frac{d y}{d x} = \frac{1}{x ( ln ( 2 ) )}

f (x) = (\frac{b}{a + z ^{2}})^{7}

\int \frac{( 2 x + 3 )}{x + 2} d x

n = 1 \sum \infty \frac{5 n}{2 n + 5}

\frac{d}{d x} (\frac{25 - x ^{2}}{4 x})

What is (d^3)/(dx^3)(1/(1+x^2)) ?
The answer to (d^3)/(dx^3)(1/(1+x^2)) is (24x(-x^2+1))/((x^2+1)^4)