What is the integral of (4-x)^3 ?

The integral of (4-x)^3 is -((4-x)^4)/4+C

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integral of (4-x)^3

\int (4 - x)^{3} d x

- \frac{( 4 - x ) ^{4}}{4} + C

Solution steps

\int (4 - x)^{3} d x

Apply u-substitution

: \int - u^{3} d u

= \int - u^{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int u^{3} d u

Apply the Power Rule

: \frac{u ^{4}}{4}

= - \frac{u ^{4}}{4}

Substitute back

u = 4 - x

= - \frac{( 4 - x ) ^{4}}{4}

Add a constant to the solution

= - \frac{( 4 - x ) ^{4}}{4} + C

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