What is the integral of e^{0.01x} ?

The integral of e^{0.01x} is 100e^{0.01x}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{0.01x}

\int e^{0.01 x} d x

100 e^{0.01 x} + C

Solution steps

\int e^{0.01 x} d x

Apply u-substitution

: \int e^{u} \frac{1}{0.01} d u

= \int e^{u} \frac{1}{0.01} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{0.01} \cdot \int e^{u} d u

Simplify

= 100 \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 100 e^{u}

Substitute back

u = 0.01 x

= 100 e^{0.01 x}

Add a constant to the solution

= 100 e^{0.01 x} + C

\frac{d}{d x} (4 8 x)

y^{^{'}} = y (3 - y)

x \to 0 - lim (csc (x) - \frac{1}{x})

\int 3^{\frac{x}{2}} d x

\frac{\partial}{\partial x} (7 yz ln (x))