What is the derivative of \sqrt[4]{8x} ?

The derivative of \sqrt[4]{8x} is 1/(2\sqrt[4]{2)x^{3/4}}

What is the first derivative of \sqrt[4]{8x} ?

The first derivative of \sqrt[4]{8x} is 1/(2\sqrt[4]{2)x^{3/4}}

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\frac{d}{d x} (4 8 x)

\frac{1}{2 4 2 x ^{\frac{3}{4}}}

Solution steps

\frac{d}{d x} (4 8 x)

Apply the chain rule:

\frac{1}{4 ( 8 x ) ^{\frac{3}{4}}} \frac{d}{d x} (8 x)

= \frac{1}{4 ( 8 x ) ^{\frac{3}{4}}} \frac{d}{d x} (8 x)

\frac{d}{d x} (8 x) = 8

= \frac{1}{4 ( 8 x ) ^{\frac{3}{4}}} \cdot 8

Simplify

\frac{1}{4 ( 8 x ) ^{\frac{3}{4}}} \cdot 8 : \frac{1}{2 4 2 x ^{\frac{3}{4}}}

= \frac{1}{2 4 2 x ^{\frac{3}{4}}}

y^{^{'}} = y (3 - y)

x \to 0 - lim (csc (x) - \frac{1}{x})

\int 3^{\frac{x}{2}} d x

\frac{\partial}{\partial x} (7 yz ln (x))

y = \frac{3}{x}, (1, 3)

What is the derivative of \sqrt[4]{8x} ?
The derivative of \sqrt[4]{8x} is 1/(2\sqrt[4]{2)x^{3/4}}
What is the first derivative of \sqrt[4]{8x} ?
The first derivative of \sqrt[4]{8x} is 1/(2\sqrt[4]{2)x^{3/4}}