What is the integral from 0 to 3 of 1/(x^2) ?

The integral from 0 to 3 of 1/(x^2) is diverges

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integral from 0 to 3 of 1/(x^2)

\int_{0}^{3} \frac{1}{x ^{2}} d x

diverges

Solution steps

\int_{0}^{3} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{0}^{3}

= [- \frac{1}{x}]_{0}^{3}

Compute the boundaries:

diverges

= diverges

f (x) = ln (x + 1)

x \to \infty lim (1 - \frac{2}{x})

\frac{d}{d x} (\frac{1}{( x + 2 )})

\int \frac{x ^{3}}{e ^{3 x^{4}}} d x

e^{x}, at x = 3

What is the integral from 0 to 3 of 1/(x^2) ?
The integral from 0 to 3 of 1/(x^2) is diverges