What is the first derivative of (x+62) ?

The first derivative of (x+62) is 2

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derivative of (x+62)

\frac{d}{d x} ((x + 6) 2)

2

Solution steps

\frac{d}{d x} ((x + 6) \cdot 2)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 2 (\frac{d x}{d x} + \frac{d}{d x} (6))

\frac{d x}{d x} = 1

\frac{d}{d x} (6) = 0

= 2 (1 + 0)

Simplify

= 2

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