What is implicit (dy)/(dx),5x^2+3xy-y^2=2 ?

The answer to implicit (dy)/(dx),5x^2+3xy-y^2=2 is (dy)/(dx)=(-10x-3y)/(3x-2y)

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implicit (dy)/(dx),5x^2+3xy-y^2=2

implicit derivative

\frac{d y}{d x}, 5 x^{2} + 3 x y - y^{2} = 2

\frac{d y}{d x} = \frac{- 10 x - 3 y}{3 x - 2 y}

Solution steps

5 x^{2} + 3 x y - y^{2} = 2

Treat

y

y (x)

Differentiate both sides:

10 x + 3 (y + x \frac{d y}{d x}) - 2 y \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{- 10 x - 3 y}{3 x - 2 y}

\frac{d y}{d x} = \frac{- 10 x - 3 y}{3 x - 2 y}

\frac{d}{d x} (x^{2 c o s (x)})

\frac{x}{1 + x}

y = \frac{- 1 e ^{x}}{x}, (1, - 1 e)

x^{2} y^{^{'}} + x y = 4, y (1) = 3

f (x) = 2 x^{\frac{1}{3}}

What is implicit (dy)/(dx),5x^2+3xy-y^2=2 ?
The answer to implicit (dy)/(dx),5x^2+3xy-y^2=2 is (dy)/(dx)=(-10x-3y)/(3x-2y)