What is (\partial)/(\partial u)(2usin(v)) ?

The answer to (\partial)/(\partial u)(2usin(v)) is 2sin(v)

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(\partial)/(\partial u)(2usin(v))

\frac{\partial}{\partial u} (2 u sin (v))

2 sin (v)

Solution steps

\frac{\partial}{\partial u} (2 u sin (v))

Treat

v

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 sin (v) \frac{\partial}{\partial u} (u)

Apply the common derivative:

\frac{\partial}{\partial u} (u) = 1

= 2 sin (v) \cdot 1

Simplify

= 2 sin (v)

f (x) = x^{2} - 9, (- 4, 7)

\frac{d}{d x} (\frac{x ^{2}}{7 + x})

\int_{- \infty}^{0} \frac{1}{2 - 4 x} d x

\int_{a}^{b} f (x) d x

(ln (\frac{x}{4}))^{^{'}}

What is (\partial)/(\partial u)(2usin(v)) ?
The answer to (\partial)/(\partial u)(2usin(v)) is 2sin(v)