What is the derivative of (x-1/2) ?

The derivative of (x-1/2) is 1/2

What is the first derivative of (x-1/2) ?

The first derivative of (x-1/2) is 1/2

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\frac{d}{d x} (\frac{x - 1}{2})

\frac{1}{2}

Solution steps

\frac{d}{d x} (\frac{x - 1}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{2} (\frac{d x}{d x} - \frac{d}{d x} (1))

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= \frac{1}{2} (1 - 0)

Simplify

= \frac{1}{2}

\frac{\partial}{\partial x} (\frac{90}{6 + x ^{2} + y ^{2}})

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\int (x (3 x - x) + (e^{e x} + 8)) d x

\frac{\partial}{\partial y} (x^{2} y^{2} - x y + 2)

What is the derivative of (x-1/2) ?
The derivative of (x-1/2) is 1/2
What is the first derivative of (x-1/2) ?
The first derivative of (x-1/2) is 1/2