What is the integral of (2x^3-5x+7) ?

The integral of (2x^3-5x+7) is (x^4)/2-(5x^2)/2+7x+C

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integral of (2x^3-5x+7)

\int (2 x^{3} - 5 x + 7) d x

\frac{x ^{4}}{2} - \frac{5 x ^{2}}{2} + 7 x + C

Solution steps

\int 2 x^{3} - 5 x + 7 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{3} d x - \int 5 x d x + \int 7 d x

\int 2 x^{3} d x = \frac{x ^{4}}{2}

\int 5 x d x = \frac{5 x ^{2}}{2}

\int 7 d x = 7 x

= \frac{x ^{4}}{2} - \frac{5 x ^{2}}{2} + 7 x

Add a constant to the solution

= \frac{x ^{4}}{2} - \frac{5 x ^{2}}{2} + 7 x + C

\frac{d}{d v} (u \cdot v)

f (θ) = 4 sin (θ) - θ

4 x^{2} cos (x) cot (x)

\int e^{x yz} d x

x \to 1 lim (sin (3 π x))

What is the integral of (2x^3-5x+7) ?
The integral of (2x^3-5x+7) is (x^4)/2-(5x^2)/2+7x+C