What is the derivative of f(x)=-3e^{x^2+x-1} ?

The derivative of f(x)=-3e^{x^2+x-1} is -3e^{x^2+x-1}(2x+1)

What is the first derivative of f(x)=-3e^{x^2+x-1} ?

The first derivative of f(x)=-3e^{x^2+x-1} is -3e^{x^2+x-1}(2x+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = - 3 e^{x^{2} + x - 1}

- 3 e^{x^{2} + x - 1} (2 x + 1)

Solution steps

\frac{d}{d x} (- 3 e^{x^{2} + x - 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{d}{d x} (e^{x^{2} + x - 1})

Apply the chain rule:

e^{x^{2} + x - 1} \frac{d}{d x} (x^{2} + x - 1)

= e^{x^{2} + x - 1} \frac{d}{d x} (x^{2} + x - 1)

\frac{d}{d x} (x^{2} + x - 1) = 2 x + 1

= - 3 e^{x^{2} + x - 1} (2 x + 1)

x^{2} y^{^{'}} + 2 x y = ln (x), y (1) = 7

y = 4 + x

\frac{d ^{2} y}{d x ^{2}} + 8 \frac{d y}{d x} + 16 y = 0

cos (π x), 0

\frac{16}{x}

What is the derivative of f(x)=-3e^{x^2+x-1} ?
The derivative of f(x)=-3e^{x^2+x-1} is -3e^{x^2+x-1}(2x+1)
What is the first derivative of f(x)=-3e^{x^2+x-1} ?
The first derivative of f(x)=-3e^{x^2+x-1} is -3e^{x^2+x-1}(2x+1)