What is the integral of e+sec^2(x)-e^x ?

The integral of e+sec^2(x)-e^x is ex+tan(x)-e^x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e+sec^2(x)-e^x

\int e + sec^{2} (x) - e^{x} d x

e x + tan (x) - e^{x} + C

Solution steps

\int e + sec^{2} (x) - e^{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e d x + \int sec^{2} (x) d x - \int e^{x} d x

\int e d x = e x

\int sec^{2} (x) d x = tan (x)

\int e^{x} d x = e^{x}

= e x + tan (x) - e^{x}

Add a constant to the solution

= e x + tan (x) - e^{x} + C

f (x) = x^{3} + 2

\frac{d y}{d x} = x y^{3} (1 + x^{2})^{- \frac{1}{2}}

\frac{d}{d x} (x^{3} - y^{3})

\frac{d}{d x} (\frac{2}{9 x ^{\frac{5}{3}}})

y^{2} = x + 6, y^{2} = 2 - x

What is the integral of e+sec^2(x)-e^x ?
The integral of e+sec^2(x)-e^x is ex+tan(x)-e^x+C