What is the derivative of f(x)=x^3+2 ?

The derivative of f(x)=x^3+2 is 3x^2

What is the first derivative of f(x)=x^3+2 ?

The first derivative of f(x)=x^3+2 is 3x^2

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derivative of

f (x) = x^{3} + 2

3 x^{2}

Solution steps

\frac{d}{d x} (x^{3} + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (2)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2) = 0

= 3 x^{2} + 0

Simplify

= 3 x^{2}

\frac{d y}{d x} = x y^{3} (1 + x^{2})^{- \frac{1}{2}}

\frac{d}{d x} (x^{3} - y^{3})

\frac{d}{d x} (\frac{2}{9 x ^{\frac{5}{3}}})

y^{2} = x + 6, y^{2} = 2 - x

\frac{d}{d x} (4 cos (3 x))

What is the derivative of f(x)=x^3+2 ?
The derivative of f(x)=x^3+2 is 3x^2
What is the first derivative of f(x)=x^3+2 ?
The first derivative of f(x)=x^3+2 is 3x^2