What is inverse oflaplace 8/(s^4) ?

The answer to inverse oflaplace 8/(s^4) is (4t^3)/3

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inverse oflaplace 8/(s^4)

inverse laplace

\frac{8}{s ^{4}}

\frac{4 t ^{3}}{3}

Solution steps

L^{- 1} {\frac{8}{s ^{4}}}

= L^{- 1} {\frac{4}{3} \cdot \frac{6}{s ^{4}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= \frac{4}{3} L^{- 1} {\frac{6}{s ^{4}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{( n ) !}{s ^{n + 1}}} = t^{n}

L^{- 1} {\frac{6}{s ^{4}}} = t^{3}

= \frac{4}{3} t^{3}

= \frac{4 t ^{3}}{3}

x y + y^{^{'}} = 2 x

f^{^{'}} (x) = \frac{x ^{2} + 3}{cos ( x )}

(\frac{10}{3}) t^{2}

\frac{d}{d n} ((1 + i)^{n} ln (1 + i) + (1 - i)^{n} ln (1 - i))

x \to 5 + lim (- \frac{3}{2} x + \frac{7}{2})

What is inverse oflaplace 8/(s^4) ?
The answer to inverse oflaplace 8/(s^4) is (4t^3)/3