What is the integral of e^{2x}*sin(x) ?

The integral of e^{2x}*sin(x) is -(e^{2x}cos(x))/5+(2e^{2x}sin(x))/5+C

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integral of e^{2x}*sin(x)

\int e^{2 x} \cdot sin (x) d x

- \frac{e ^{2 x} cos ( x )}{5} + \frac{2 e ^{2 x} sin ( x )}{5} + C

Solution steps

\int e^{2 x} sin (x) d x

Apply Integration By Parts

: - e^{2 x} cos (x) - \int - 2 e^{2 x} cos (x) d x

= - e^{2 x} cos (x) - \int - 2 e^{2 x} cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - e^{2 x} cos (x) - (- 2 \cdot \int e^{2 x} cos (x) d x)

Apply Integration By Parts

: e^{2 x} sin (x) - \int e^{2 x} \cdot 2 sin (x) d x

= - e^{2 x} cos (x) - (- 2 (e^{2 x} sin (x) - \int e^{2 x} \cdot 2 sin (x) d x))

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - e^{2 x} cos (x) - (- 2 (e^{2 x} sin (x) - 2 \cdot \int e^{2 x} sin (x) d x))

Therefore

\int e^{2 x} sin (x) d x = - e^{2 x} cos (x) - (- 2 (e^{2 x} sin (x) - 2 \cdot \int e^{2 x} sin (x) d x))

Isolate

\int e^{2 x} sin (x) d x

= - \frac{e ^{2 x} cos ( x )}{5} + \frac{2 e ^{2 x} sin ( x )}{5}

Add a constant to the solution

= - \frac{e ^{2 x} cos ( x )}{5} + \frac{2 e ^{2 x} sin ( x )}{5} + C

f (x) = \frac{1}{6} x^{4}, at x = - 1

1 - e^{- t} sin (2 t)

\frac{d}{d x} (8 x (x^{2} + 3)^{3})

f (x) = 16 - x^{2}

(4 x)^{^{'}}

What is the integral of e^{2x}*sin(x) ?
The integral of e^{2x}*sin(x) is -(e^{2x}cos(x))/5+(2e^{2x}sin(x))/5+C