What is the solution for (dy)/(dx)=e^{5y+6x},y(0)=2 ?

The solution for (dy)/(dx)=e^{5y+6x},y(0)=2 is y=-(ln(-5/6 e^{6x}+1/(e^{10)}+5/6))/5

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(dy)/(dx)=e^{5y+6x},y(0)=2

\frac{d y}{d x} = e^{5 y + 6 x}, y (0) = 2

y = - \frac{ln ( - \frac{5}{6} e ^{6 x} + \frac{1}{e ^{10}} + \frac{5}{6} )}{5}

Solution steps

\frac{d y}{d x} = e^{5 y + 6 x}

Solve separable ODE:

y = - \frac{ln ( - \frac{5}{6} e ^{6 x} + \frac{1}{e ^{10}} + \frac{5}{6} )}{5}

y = - \frac{ln ( - \frac{5}{6} e ^{6 x} + \frac{1}{e ^{10}} + \frac{5}{6} )}{5}

\frac{d}{d x} (\frac{( 1 - 5 x )}{( 1 + 5 x )})

\frac{d y}{d x} = y (1 - 0.0002 y)

ln (x^{2} + 4)

x \to 0 lim (2 f (x) - 1)

y^{^{''}} + 16 y = 4 t^{2}

What is the solution for (dy)/(dx)=e^{5y+6x},y(0)=2 ?
The solution for (dy)/(dx)=e^{5y+6x},y(0)=2 is y=-(ln(-5/6 e^{6x}+1/(e^{10)}+5/6))/5