What is the tangent of 7sqrt(x),\at x=4 ?

The tangent of 7sqrt(x),\at x=4 is y= 7/4 x+7

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tangent of 7sqrt(x),\at x=4

tangent of

7 x, at x = 4

y = \frac{7}{4} x + 7

Solution steps

Find the tangent point:

(4, 14)

Find the slope of

y = 7 x : \frac{d y}{d x} = \frac{7}{2 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{7}{4}

Find the line with slope m=

\frac{7}{4}

and passing through

(4, 14) : y = \frac{7}{4} x + 7

y = \frac{7}{4} x + 7

\int 8 u^{\frac{9}{8}} d u

x = y^{2} - 2, (- 2, 2)

y^{'} = y (1 - 0.0008 y)

f (x) = \frac{2 x}{x - 1}

\int sin (x) \cdot cos^{2} (x) d x

What is the tangent of 7sqrt(x),\at x=4 ?
The tangent of 7sqrt(x),\at x=4 is y= 7/4 x+7