What is (\partial)/(\partial y)(tan(2x-y)) ?

The answer to (\partial)/(\partial y)(tan(2x-y)) is -sec^2(2x-y)

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(\partial)/(\partial y)(tan(2x-y))

\frac{\partial}{\partial y} (tan (2 x - y))

- sec^{2} (2 x - y)

Solution steps

\frac{\partial}{\partial y} (tan (2 x - y))

Treat

x

as a constant

Apply the chain rule:

sec^{2} (2 x - y) \frac{\partial}{\partial y} (2 x - y)

= sec^{2} (2 x - y) \frac{\partial}{\partial y} (2 x - y)

\frac{\partial}{\partial y} (2 x - y) = - 1

= sec^{2} (2 x - y) (- 1)

Simplify

= - sec^{2} (2 x - y)

n = 1 \sum \infty \frac{3}{( n ( n + 2 ) )}

\int 24 x e^{2.4 x} d x

\frac{d}{d x} (x + 2 x)

\frac{\partial}{\partial x} (x e^{- x^{2}})

y = sec (x) - 2 cos (x), (\frac{π}{3}, 1)

What is (\partial)/(\partial y)(tan(2x-y)) ?
The answer to (\partial)/(\partial y)(tan(2x-y)) is -sec^2(2x-y)