What is the integral from-2 to-1 of (15x^{-4}) ?

The integral from-2 to-1 of (15x^{-4}) is 35/8

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integral from-2 to-1 of (15x^{-4})

\int_{- 2}^{- 1} (15 x^{- 4}) d x

\frac{35}{8}

Decimal Notation

4.375

Solution steps

\int_{- 2}^{- 1} 15 x^{- 4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 15 \cdot \int_{- 2}^{- 1} x^{- 4} d x

Apply the Power Rule

: [- \frac{1}{3 x ^{3}}]_{- 2}^{- 1}

= 15 [- \frac{1}{3 x ^{3}}]_{- 2}^{- 1}

Compute the boundaries:

\frac{7}{24}

= 15 \cdot \frac{7}{24}

Simplify

= \frac{35}{8}

\int 3 x^{2} x^{3} + 2 d x

\int_{0}^{3} 3 x - 5 d x

\frac{d}{d x} ((x^{2} + 2)^{7})

\frac{d}{d t} (2 arctan (t))

x^{^{'}} = x^{2} e^{- 2 t}

What is the integral from-2 to-1 of (15x^{-4}) ?
The integral from-2 to-1 of (15x^{-4}) is 35/8