What is the derivative of (x^2+2^7) ?

The derivative of (x^2+2^7) is 14x(x^2+2)^6

What is the first derivative of (x^2+2^7) ?

The first derivative of (x^2+2^7) is 14x(x^2+2)^6

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\frac{d}{d x} ((x^{2} + 2)^{7})

14 x (x^{2} + 2)^{6}

Solution steps

\frac{d}{d x} ((x^{2} + 2)^{7})

Apply the chain rule:

7 (x^{2} + 2)^{6} \frac{d}{d x} (x^{2} + 2)

= 7 (x^{2} + 2)^{6} \frac{d}{d x} (x^{2} + 2)

\frac{d}{d x} (x^{2} + 2) = 2 x

= 7 (x^{2} + 2)^{6} \cdot 2 x

Simplify

= 14 x (x^{2} + 2)^{6}

\frac{d}{d t} (2 arctan (t))

x^{^{'}} = x^{2} e^{- 2 t}

\int_{0}^{1} (x - e^{x})^{2} d x

\int \frac{1}{( t + 1 ) ^{2}} d t

\int_{0}^{1} \frac{3}{1 - x ^{2}} d x

What is the derivative of (x^2+2^7) ?
The derivative of (x^2+2^7) is 14x(x^2+2)^6
What is the first derivative of (x^2+2^7) ?
The first derivative of (x^2+2^7) is 14x(x^2+2)^6