What is the derivative of f(x)=ln(ln(4x)) ?

The derivative of f(x)=ln(ln(4x)) is 1/(xln(4x))

What is the first derivative of f(x)=ln(ln(4x)) ?

The first derivative of f(x)=ln(ln(4x)) is 1/(xln(4x))

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derivative of

f (x) = ln (ln (4 x))

\frac{1}{x ln ( 4 x )}

Solution steps

\frac{d}{d x} (ln (ln (4 x)))

Apply the chain rule:

\frac{1}{ln ( 4 x )} \frac{d}{d x} (ln (4 x))

= \frac{1}{ln ( 4 x )} \frac{d}{d x} (ln (4 x))

\frac{d}{d x} (ln (4 x)) = \frac{1}{x}

= \frac{1}{ln ( 4 x )} \cdot \frac{1}{x}

Simplify

\frac{1}{ln ( 4 x )} \cdot \frac{1}{x} : \frac{1}{x ln ( 4 x )}

= \frac{1}{x ln ( 4 x )}

\frac{d x}{d y} = \frac{y - x}{y + x}

(1 + x^{2}) y^{^{''}} = - 2 x y^{^{'}}

\frac{\partial}{\partial θ} (e^{r} cos (θ))

\int_{2}^{4} \frac{2}{x} - \frac{1}{8} x d x

y = - 8 x^{3} + 9 x^{2} + 6 x - 5

What is the derivative of f(x)=ln(ln(4x)) ?
The derivative of f(x)=ln(ln(4x)) is 1/(xln(4x))
What is the first derivative of f(x)=ln(ln(4x)) ?
The first derivative of f(x)=ln(ln(4x)) is 1/(xln(4x))