What is (\partial)/(\partial x)(x^2*sin^2(yz)) ?

The answer to (\partial)/(\partial x)(x^2*sin^2(yz)) is 2xsin^2(yz)

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(\partial)/(\partial x)(x^2*sin^2(yz))

\frac{\partial}{\partial x} (x^{2} \cdot sin^{2} (yz))

2 x sin^{2} (yz)

Solution steps

\frac{\partial}{\partial x} (x^{2} sin^{2} (yz))

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin^{2} (yz) \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= sin^{2} (yz) \cdot 2 x^{2 - 1}

Simplify

= 2 x sin^{2} (yz)

y = x, y = x + 6, 0 < x < 5

\int_{- \frac{1}{3}}^{\frac{1}{3}} \frac{1}{( 1 - x ^{2} )} d x

\frac{\partial}{\partial y} (- \frac{y}{x})

\int_{0}^{\frac{π}{3}} cos (\frac{2 x}{3}) d x

x^{2} + 5 x + 1, x^{3} + x^{2} + x + 1

What is (\partial)/(\partial x)(x^2*sin^2(yz)) ?
The answer to (\partial)/(\partial x)(x^2*sin^2(yz)) is 2xsin^2(yz)