What is the integral of 6cos(6x)-5 ?

The integral of 6cos(6x)-5 is sin(6x)-5x+C

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integral of 6cos(6x)-5

\int 6 cos (6 x) - 5 d x

sin (6 x) - 5 x + C

Solution steps

\int 6 cos (6 x) - 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 6 cos (6 x) d x - \int 5 d x

\int 6 cos (6 x) d x = sin (6 x)

\int 5 d x = 5 x

= sin (6 x) - 5 x

Add a constant to the solution

= sin (6 x) - 5 x + C

\frac{\partial}{\partial x} (x - 1)

\frac{7}{1 + x}

\frac{\partial}{\partial x} (3 x^{2} y - 1)

\int \frac{6 x + 2}{x ^{2} + 9} d x

\frac{d}{d x} (\frac{x + 3}{x + 2})