What is the integral of-3sin(t) ?

The integral of-3sin(t) is 3cos(t)+C

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integral of-3sin(t)

\int - 3 sin (t) d t

3 cos (t) + C

Solution steps

\int - 3 sin (t) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 3 \cdot \int sin (t) d t

Use the common integral:

\int sin (t) d t = - cos (t)

= - 3 (- cos (t))

Simplify

= 3 cos (t)

Add a constant to the solution

= 3 cos (t) + C

(t - 1) 1 (t - 1)

\int tan (θ) sec^{2} (θ) d θ

\frac{d}{d x} (\frac{x ^{2} - 2}{2 x + 1})

\int ln (x^{2}) d x

\frac{x d y}{d x} + y = e^{- x}