What is the slope ofintercept (-10,-7),(-5,-9) ?

The slope ofintercept (-10,-7),(-5,-9) is y=-2/5 x-11

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slope ofintercept (-10,-7),(-5,-9)

slope intercept

(- 10, - 7), (- 5, - 9)

y = - \frac{2}{5} x - 11

Solution steps

Compute the slope

(- 10, - 7), (- 5, - 9) : m = - \frac{2}{5}

Compute the

y

intercept:

b = - 11

Construct the line equation

y = mx + b

where

m = - \frac{2}{5}

and

b = - 11

y = - \frac{2}{5} x - 11

f (x) = arctan (\frac{2 x}{1 - x ^{2}})

\frac{\partial}{\partial s} (1 + s t)

\int \frac{11 x + 64}{x ^{2} + 13 x + 40} d x

x \to 0 lim (\frac{( x ^{2} )}{e - 1})

What is the slope ofintercept (-10,-7),(-5,-9) ?
The slope ofintercept (-10,-7),(-5,-9) is y=-2/5 x-11