What is the tangent of f(x)=5x^3-5x^2+2,(1,2) ?

The tangent of f(x)=5x^3-5x^2+2,(1,2) is y=5x-3

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tangent of f(x)=5x^3-5x^2+2,(1,2)

tangent of

f (x) = 5 x^{3} - 5 x^{2} + 2, (1, 2)

y = 5 x - 3

Solution steps

Find the slope of

f (x) = 5 x^{3} - 5 x^{2} + 2 : \frac{df ( x )}{d x} = 15 x^{2} - 10 x

Compute the slope of

f (x) = 5 x^{3} - 5 x^{2} + 2

(1, 2) : m = 5

Find the line with slope m=

5

and passing through

(1, 2) : y = 5 x - 3

y = 5 x - 3

x \to - 1 - lim (3 x + 3 - 5)

y^{^{'}} = \frac{( y - y ^{2} )}{t}

\frac{1}{s - 5}

y^{^{'}} + 6 y = 60, y (1) = 110

What is the tangent of f(x)=5x^3-5x^2+2,(1,2) ?
The tangent of f(x)=5x^3-5x^2+2,(1,2) is y=5x-3