What is (\partial)/(\partial x)(yz-xw) ?

The answer to (\partial)/(\partial x)(yz-xw) is -w

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(\partial)/(\partial x)(yz-xw)

\frac{\partial}{\partial x} (yz - x w)

- w

Solution steps

\frac{\partial}{\partial x} (yz - x w)

Treat

y, z, w

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (yz) - \frac{\partial}{\partial x} (x w)

\frac{\partial}{\partial x} (yz) = 0

\frac{\partial}{\partial x} (x w) = w

= 0 - w

Simplify

= - w

x y^{^{''}} + 5 y^{^{'}} = 0

\frac{\partial}{\partial y} (5 x y^{3})

y = x^{2} + 5 x + 2, (- 5, 2)

f (x) = - 3 - 6 x^{2}, (- 2, 27)

What is (\partial)/(\partial x)(yz-xw) ?
The answer to (\partial)/(\partial x)(yz-xw) is -w