What is the solution for y^'=(cot(y))/t ?

The solution for y^'=(cot(y))/t is y=arccos((c_{1})/t)+2pin,y=-arccos((c_{1})/t)+2pin

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y^'=(cot(y))/t

y^{^{'}} = \frac{cot ( y )}{t}

y = arccos (\frac{c _{1}}{t}) + 2 πn, y = - arccos (\frac{c _{1}}{t}) + 2 πn

Solution steps

y^{'} (t) = \frac{cot ( y )}{t}

Solve separable ODE:

y = arccos (\frac{c _{1}}{t}) + 2 πn, y = - arccos (\frac{c _{1}}{t}) + 2 πn

y = arccos (\frac{c _{1}}{t}) + 2 πn, y = - arccos (\frac{c _{1}}{t}) + 2 πn

\int \frac{1}{3} x d x

e^{- 2 x}

(1 - x) y^{^{'}} - 4 x y^{^{'}} + 5 y = cos (x)

\frac{d}{d x} (\frac{1 - x}{e ^{x}})

\frac{\partial}{\partial x} (- y cos (- 3 x))

What is the solution for y^'=(cot(y))/t ?
The solution for y^'=(cot(y))/t is y=arccos((c_{1})/t)+2pin,y=-arccos((c_{1})/t)+2pin