What is laplacetransform e^{-2x} ?

The answer to laplacetransform e^{-2x} is 1/(s+2)

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laplacetransform e^{-2x}

laplace transform

e^{- 2 x}

\frac{1}{s + 2}

Solution steps

L {e^{- 2 x}}

Use Laplace Transform table:

L {e^{a t}} = \frac{1}{s - a}

L {e^{- 2 x}} = \frac{1}{s + 2}

= \frac{1}{s + 2}

(1 - x) y^{^{'}} - 4 x y^{^{'}} + 5 y = cos (x)

\frac{d}{d x} (\frac{1 - x}{e ^{x}})

\frac{\partial}{\partial x} (- y cos (- 3 x))

n = 2 \sum \infty \frac{( n - 1 )}{n}

- x^{4} + 2 x^{3} + 4 x^{2}

What is laplacetransform e^{-2x} ?
The answer to laplacetransform e^{-2x} is 1/(s+2)