What is the derivative of 3sin(2t) ?

The derivative of 3sin(2t) is 6cos(2t)

What is the first derivative of 3sin(2t) ?

The first derivative of 3sin(2t) is 6cos(2t)

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derivative of

3 sin (2 t)

6 cos (2 t)

Solution steps

\frac{d}{d t} (3 sin (2 t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d t} (sin (2 t))

Apply the chain rule:

cos (2 t) \frac{d}{d t} (2 t)

= cos (2 t) \frac{d}{d t} (2 t)

\frac{d}{d t} (2 t) = 2

= 3 cos (2 t) \cdot 2

Simplify

= 6 cos (2 t)

\int \frac{e ^{2 x} + 1}{e ^{2 x}} d x

y = 2^{(0.3 x - 7)} - 0.0625

y = x^{2} + 1

\frac{d}{d x} (2 1 + x)

f (x) = (x + 1)^{2}

What is the derivative of 3sin(2t) ?
The derivative of 3sin(2t) is 6cos(2t)
What is the first derivative of 3sin(2t) ?
The first derivative of 3sin(2t) is 6cos(2t)